Difference between revisions of "Specific Heat Capacity"

Revision as of 13:50, 7 June 2019

Specific heat capacity is the energy required to increase the temperature of 1kg of a material by 1°C.

The SI Units of specific heat capacity are J/kg°C.

Specific heat capacity describes how easily the temperature of a material can be changed.

Different materials have a different specific heat capacity.

Materials with a low specific heat capacity are generally good thermal conductors and materials with a high specific heat capacity are generally good thermal insulators.

NB: You do not need to remember the equation for specific heat capacity.

Specific Heat Capacity = (Energy Transferred)/[(Mass) x (Temperature Change)]

\(c = \frac{E}{m \Delta \theta}\)

Where

\(m\) = The mass of the object.

\(\Delta \theta\) = The Temperature change of the object.

8.0kg of water is heated with an energy of 1510kJ from a temperature of 11°C to a temperature of 56°C. Calculate the specific heat capacity of the water correct to two significant figures.	A 989g block of metal is heated using an immersion heater from 24°C to 39°C. A Joulemeter connected to the immersion heater reads 13,000J. Calculate the specific heat capacity of the metal correct to two significant figures.
1. State the known quantities in SI Units E = 1510kJ = 1510x10³J m = 8.0kg Δθ = 56-11 = 45°C	1. State the known quantities in SI Units E = 13,000J m = 989g = 0.989kg Δθ = 39-24 = 15°C
2. Substitute the numbers into the equation and solve. \(c = \frac{E}{m \Delta \theta}\) \(c = \frac{1510 \times 10^3}{8.0 \times 45}\) \(c = 4194.4J/kg ^\circ C\) \(c \approx 4200J/kg ^\circ C\)	2. Substitute the numbers into the equation and solve. \(c = \frac{E}{m \Delta \theta}\) \(c = \frac{13000}{0.989 \times 15}\) \(c = 876.306033J/kg ^\circ C\) \(c \approx 880J/kg ^\circ C\)

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 <math>c = \frac{E}{m \Delta \theta}</math>
-Where:
+Where
 <math>c</math> = The [[Specific Heat Capacity]] of the [[material]].