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Difference between revisions of "Specific Heat Capacity"

(Example Calculations)
(Example Calculations)
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===Example Calculations===
 
===Example Calculations===
 
{| class="wikitable"
 
{| class="wikitable"
| style="height:20px; width:300px; text-align:center;" |8.0kg of [[water]] is [[heat]]ed with an [[energy]] of 1510kJ from a [[temperature]] of 11°C to a [[temperature]] of 56°C. Calculate the specific heat capacity of the [[water]] correct to two [[Significant Figures|significant figures]].
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| style="height:20px; width:300px; text-align:center;" |8.0kg of [[water]] is [[heat]]ed with an [[energy]] of 1510kJ from a [[temperature]] of 11°C to a [[temperature]] of 56°C. Calculate the '''specific heat capacity''' of the [[water]] correct to two [[Significant Figures|significant figures]].
 
| style="height:20px; width:300px; text-align:center;" |A 989g block of [[metal]] is [[heat]]ed using an [[Immersion Heater|immersion heater]] from 24°C to 39°C. A [[Joulemeter]] connected to the [[Immersion Heater|immersion heater]] reads 13,000J. Calculate the '''specific heat capacity''' of the [[metal]] correct to two [[Significant Figures|significant figures]].
 
| style="height:20px; width:300px; text-align:center;" |A 989g block of [[metal]] is [[heat]]ed using an [[Immersion Heater|immersion heater]] from 24°C to 39°C. A [[Joulemeter]] connected to the [[Immersion Heater|immersion heater]] reads 13,000J. Calculate the '''specific heat capacity''' of the [[metal]] correct to two [[Significant Figures|significant figures]].
 
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Revision as of 11:26, 6 March 2019

Key Stage 4

Meaning

Specific heat capacity is the energy required to increase the temperature of 1kg of a material by 1°C.

About Specific Heat Capacity

The SI Units of specific heat capacity are J/kg°C.
Specific heat capacity describes how easily the temperature of a material can be changed.
Materials with a low specific heat capacity are generally good thermal conductors and materials with a high specific heat capacity are generally good thermal insulators.

Equation

NB: You do not need to remember the equation for specific heat capacity.

Specific Heat Capacity = (Energy Transferred)/[(Mass) x (Temperature Change)]

\(c = \frac{E}{m \Delta \theta}\)

Where\[c\] = The Specific Heat Capacity of the material.

\(E\) = The Energy transferred to the object, by heating.

\(m\) = The mass of the object.

\(\Delta \theta\) = The Temperature change of the object.

Example Calculations

8.0kg of water is heated with an energy of 1510kJ from a temperature of 11°C to a temperature of 56°C. Calculate the specific heat capacity of the water correct to two significant figures. A 989g block of metal is heated using an immersion heater from 24°C to 39°C. A Joulemeter connected to the immersion heater reads 13,000J. Calculate the specific heat capacity of the metal correct to two significant figures.
1. State the known quantities in SI Units

E = 1510kJ = 1510x103J

m = 8.0kg

Δθ = 56-11 = 45°C

1. State the known quantities in SI Units

E = 13,000J

m = 989g = 0.989kg

Δθ = 39-24 = 15°C

2. Substitute the numbers into the equation and solve.

\(c = \frac{E}{m \Delta \theta}\)

\(c = \frac{1510 \times 10^3}{8.0 \times 45}\)

\(c = 4194.4J/kg ^\circ C\)

\(c \approx 4200J/kg ^\circ C\)

2. Substitute the numbers into the equation and solve.

\(c = \frac{E}{m \Delta \theta}\)

\(c = \frac{13000}{0.989 \times 15}\)

\(c = 876.306033J/kg ^\circ C\)

\(c \approx 880J/kg ^\circ C\)