Yield (Chemistry) - Revision history

Ellen References at 12:15, 25 December 2019

2019-12-25T12:15:11Z

Ellen References at 17:13, 29 November 2019

2019-11-29T17:13:07Z

Ellen References at 13:29, 15 November 2019

2019-11-15T13:29:52Z

NRJC: /* About Yield */

2019-01-27T18:54:15Z

‎About Yield

NRJC: /* Examples */

2019-01-12T17:54:08Z

‎Examples

NRJC: /* Examples */

2019-01-12T17:53:38Z

‎Examples

NRJC: /* Examples */

2019-01-12T17:51:58Z

‎Examples

NRJC: /* Examples */

2019-01-12T17:49:56Z

‎Examples

NRJC: /* Examples */

2019-01-12T17:12:51Z

‎Examples

NRJC: /* Examples */

2019-01-12T17:05:23Z

‎Examples

← Older revision		Revision as of 12:15, 25 December 2019
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	:[https://www.amazon.co.uk/gp/product/1782948147/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948147&linkCode=as2&tag=nrjc-21&linkId=f63dcd8345f4e49c717b39a228a36c7c ''Yields, pages 172-174, 189-191, 201-203, GCSE Chemistry, CGP, Edexcel '']		:[https://www.amazon.co.uk/gp/product/1782948147/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948147&linkCode=as2&tag=nrjc-21&linkId=f63dcd8345f4e49c717b39a228a36c7c ''Yields, pages 172-174, 189-191, 201-203, GCSE Chemistry, CGP, Edexcel '']
	:[https://www.amazon.co.uk/gp/product/1782945725/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945725&linkCode=as2&tag=nrjc-21&linkId=694be7494de75af3349537d34e13f7f0 ''Yields, pages 66, 68, GCSE Chemistry; The Revision Guide, CGP, Edexcel '']		:[https://www.amazon.co.uk/gp/product/1782945725/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945725&linkCode=as2&tag=nrjc-21&linkId=694be7494de75af3349537d34e13f7f0 ''Yields, pages 66, 68, GCSE Chemistry; The Revision Guide, CGP, Edexcel '']
		+
		+	====OCR====
		+	:[https://www.amazon.co.uk/gp/product/0198359829/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0198359829&linkCode=as2&tag=nrjc-21&linkId=90e8d7b4f039d53035238fa0320fe00b ''Yield, pages 158-161, 190, 200-203, 205, Gateway GCSE Chemistry, Oxford, OCR '']
		+	:[https://www.amazon.co.uk/gp/product/1782945679/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945679&linkCode=as2&tag=nrjc-21&linkId=a2db42f7b4bdf10cafaafa3bb9120940 ''Yield, pages 66, 74, 80, 82, Gateway GCSE Chemistry; The Revision Guide, CGP, OCR '']
		+	:[https://www.amazon.co.uk/gp/product/1782945660/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945660&linkCode=as2&tag=nrjc-21&linkId=83aa4500ad7759e7f401a1c5ba5df758 ''Yields (in agriculture), pages 86, 87, Gateway GCSE Biology; The Revision Guide, CGP, OCR '']

← Older revision		Revision as of 17:13, 29 November 2019
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	:[https://www.amazon.co.uk/gp/product/1782945962/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945962&linkCode=as2&tag=nrjc-21&linkId=476bb5c8d1dfb5c08ac81b6d4d1c98d8 ''Yields, pages 141, 144, 216-218, GCSE Chemistry, CGP, AQA '']		:[https://www.amazon.co.uk/gp/product/1782945962/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945962&linkCode=as2&tag=nrjc-21&linkId=476bb5c8d1dfb5c08ac81b6d4d1c98d8 ''Yields, pages 141, 144, 216-218, GCSE Chemistry, CGP, AQA '']
	:[https://www.amazon.co.uk/gp/product/1782945571/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945571&linkCode=as2&tag=nrjc-21&linkId=9e29fad914244909903e5e93f8a01d272 ''Yields, pages 45, 49, GCSE Chemistry; The Revision Guide, CGP, AQA '']		:[https://www.amazon.co.uk/gp/product/1782945571/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945571&linkCode=as2&tag=nrjc-21&linkId=9e29fad914244909903e5e93f8a01d272 ''Yields, pages 45, 49, GCSE Chemistry; The Revision Guide, CGP, AQA '']
		+
		+	====Edexcel====
		+
		+	:[https://www.amazon.co.uk/gp/product/1782948147/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948147&linkCode=as2&tag=nrjc-21&linkId=f63dcd8345f4e49c717b39a228a36c7c ''Yields, pages 172-174, 189-191, 201-203, GCSE Chemistry, CGP, Edexcel '']
		+	:[https://www.amazon.co.uk/gp/product/1782945725/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945725&linkCode=as2&tag=nrjc-21&linkId=694be7494de75af3349537d34e13f7f0 ''Yields, pages 66, 68, GCSE Chemistry; The Revision Guide, CGP, Edexcel '']

← Older revision		Revision as of 13:29, 15 November 2019
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	'''Yield''' = 11.7g		'''Yield''' = 11.7g
	\|}		\|}
		+
		+	===References===
		+	====AQA====
		+
		+	:[https://www.amazon.co.uk/gp/product/0008158754/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0008158754&linkCode=as2&tag=nrjc-21&linkId=27ad53b0283feeff7fc5ae04a9e205f621 ''Yield, page 66-7, GCSE Biology; Student Book, Collins, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1471851346/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1471851346&linkCode=as2&tag=nrjc-21&linkId=3ac654f4b0da781c49c855a1af4c92ea ''Yield, page 78, GCSE Chemistry, Hodder, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/178294639X/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=178294639X&linkCode=as2&tag=nrjc-21&linkId=51599bb45a2bfaf7c1b6a978b2ca2616 ''Yield, pages 184-186, GCSE Combined Science Trilogy; Chemistry, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/0198359381/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0198359381&linkCode=as2&tag=nrjc-21&linkId=47c8d1ae58d8b3a5e2094cd447154558 ''Yield, pages 68-71, GCSE Chemistry; Third Edition, Oxford University Press, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/0008158762/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0008158762&linkCode=as2&tag=nrjc-21&linkId=a0fffa35b3ea49a63404f6704e0df7cc ''Yield, pages 97, 216-219, 317, 323, GCSE Chemistry; Student Book, Collins, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782945962/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945962&linkCode=as2&tag=nrjc-21&linkId=476bb5c8d1dfb5c08ac81b6d4d1c98d8 ''Yields, pages 141, 144, 216-218, GCSE Chemistry, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782945571/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945571&linkCode=as2&tag=nrjc-21&linkId=9e29fad914244909903e5e93f8a01d272 ''Yields, pages 45, 49, GCSE Chemistry; The Revision Guide, CGP, AQA '']

@@ Line 4: / Line 4: @@
 ===About Yield===
-: The theoretical '''yield''' of [[product]] form a [[Chemical Reaction|chemical reaction]] can be calculated using the [[Balanced Symbol Equation|balanced symbol equation]] and the [[Relative Formula Mass|relative formula masses]] of all the [[molecule]]s involved.
+: The theoretical '''yield''' of [[product]] from a [[Chemical Reaction|chemical reaction]] can be calculated using the [[Balanced Symbol Equation|balanced symbol equation]] and the [[Relative Formula Mass|relative formula masses]] of all the [[molecule]]s involved.
 : The experimental '''yield''' from a [[Chemical Reaction|chemical reaction]] is often not as large as the theoretical '''yield''' because not all of the [[reactant]]s will [[Chemical Reaction|react]]. This experimental '''yield''' is often expressed as a [[percentage]] of the theoretical '''yield''' and is known as the [[Percentage Yield]].

@@ Line 24: / Line 24: @@
 CH<sub>4</sub> + 2O<sub>2</sub> → 2H<sub>2</sub>O + CO<sub>2</sub>
-| style="height:20px; width:300px; text-align:left;" |
+| style="height:20px; width:300px; text-align:center;" |
 '''Write the Balanced Symbol Equation'''

@@ Line 9: / Line 9: @@
 ===Examples===
 {| class="wikitable"
-| style="height:20px; width:200px; text-align:center;" |
+| style="height:20px; width:300px; text-align:center;" |
 Calculate the '''yield''' of [[Magnesium Oxide]] given 48g of [[Magnesium]] and excess [[Oxygen]].
-|style="height:20px; width:200px; text-align:center;" |
+| style="height:20px; width:300px; text-align:center;" |
 Find the '''yield''' of [[Water]] when 320g of [[Methane]] [[Chemical reaction|reacts]] with excess [[Oxygen]].
-| style="height:20px; width:200px; text-align:center;" |
+| style="height:20px; width:300px; text-align:center;" |
 Find the '''yield''' of [[Sodium Chloride]] when 7.3 of [[Hydrochloric Acid]] [[Chemical Reaction|reacts]] with excess [[Sodium Hydroxide]].
 |-
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
 '''Write the Balanced Symbol Equation'''
 Mg + O<sub>2</sub> → 2MgO
-| style="height:20px; width:200px; text-align:center;" |
+| style="height:20px; width:300px; text-align:center;" |
 '''Write the Balanced Symbol Equation'''
 CH<sub>4</sub> + 2O<sub>2</sub> → 2H<sub>2</sub>O + CO<sub>2</sub>
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
 '''Write the Balanced Symbol Equation'''
 NaOH + HCl → NaCl + H<sub>2</sub>O
 |-
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].
+'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
 M<sub>r</sub> of Mg = 24g
@@ Line 36: / Line 36: @@
 M<sub>r</sub> of MgO = 40g
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].
+'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
 M<sub>r</sub> of CH<sub>4</sub> = 16g
@@ Line 43: / Line 43: @@
 M<sub>r</sub> of H<sub>2</sub>O = 18g
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].
+'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
 M<sub>r</sub> of NaOH = 40g
@@ Line 52: / Line 52: @@
 M<sub>r</sub> of NaCl = 58.5g
 |-
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
+'''State the [[ratio]] of [[mole]]s of each [[chemical]] needed.'''
 [[mole]]s of Mg are needed for every 2 [[mole]]s of MgO
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
+'''State the [[ratio]] of [[mole]]s of each [[chemical]] needed.'''
 [[mole]] of CH<sub>4</sub> is needed for every 2 [[mole]]s H<sub>2</sub>O
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
+'''State the [[ratio]] of [[mole]]s of each [[chemical]] needed.'''
 [[mole]] of HCl and NaOH are needed for every 1 [[mole]] of NaCl
@@ Line 69: / Line 69: @@
 |-
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-Find the number of [[mole]]s supplied of the known [[mass]].
+'''Find the number of [[mole]]s supplied of the known [[mass]].'''
 No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
@@ Line 84: / Line 84: @@
 '''Yield''' = 80g
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-Find the number of [[mole]]s supplied of the known [[mass]].
+'''Find the number of [[mole]]s supplied of the known [[mass]].'''
 No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
@@ Line 99: / Line 99: @@
 '''Yield''' = 720g
-| style="height:20px; width:200px; text-align:left;" |
+| style="height:20px; width:300px; text-align:left;" |
-Find the number of [[mole]]s supplied of the known [[mass]].
+'''Find the number of [[mole]]s supplied of the known [[mass]].'''
 No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>

@@ Line 12: / Line 12: @@
 Calculate the '''yield''' of [[Magnesium Oxide]] given 48g of [[Magnesium]] and excess [[Oxygen]].
 |style="height:20px; width:200px; text-align:center;" |
-Find the '''yield''' of [[Carbon Dioxide]] when 32g of [[Methane]] [[Chemical reaction|reacts]] with excess [[Oxygen]].
+Find the '''yield''' of [[Water]] when 320g of [[Methane]] [[Chemical reaction|reacts]] with excess [[Oxygen]].
 | style="height:20px; width:200px; text-align:center;" |
-Find the '''yield''' of [[Sodium Chloride]] when 80g of [[Sodium Hydroxide]] [[Chemical Reaction|react]] with 73g of [[Hydrochloric Acid]].
+Find the '''yield''' of [[Sodium Chloride]] when 7.3 of [[Hydrochloric Acid]] [[Chemical Reaction|reacts]] with excess [[Sodium Hydroxide]].
 |-
 | style="height:20px; width:200px; text-align:left;" |
@@ Line 32: / Line 32: @@
 Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].
-M<sub>r</sub> of 2Mg = 48g
+M<sub>r</sub> of Mg = 24g
-M<sub>r</sub> of 2MgO = 80g
+M<sub>r</sub> of MgO = 40g
 | style="height:20px; width:200px; text-align:left;" |
@@ Line 41: / Line 41: @@
 M<sub>r</sub> of CH<sub>4</sub> = 16g
-M<sub>r</sub> of CO<sub>2</sub> = 44g
+M<sub>r</sub> of H<sub>2</sub>O = 18g
 | style="height:20px; width:200px; text-align:left;" |
@@ Line 60: / Line 60: @@
 State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
-[[mole]] of CH<sub>4</sub> is needed for every 1 [[mole]] of CO<sub>2</sub>
+[[mole]] of CH<sub>4</sub> is needed for every 2 [[mole]]s H<sub>2</sub>O
 | style="height:20px; width:200px; text-align:left;" |
@@ Line 76: / Line 76: @@
 No. [[Mole]]s = <math>\frac{48}{24}</math>
-No. [[Mole]]s = 2 Mole
+No. [[Mole]]s = 2 mol
-Therefore 1 [[mole]] of O<sub>2</sub> is needed.
+Therefore 2 [[mole]]s of MgO is produced.
-[[mole]] of O<sub>2</sub> = 32g
+[[mole]]s of MgO = 40x2
 | style="height:20px; width:200px; text-align:left;" |
@@ Line 87: / Line 89: @@
 No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
-No. [[Mole]]s = <math>\frac{32}{16}</math>
+No. [[Mole]]s = <math>\frac{320}{16}</math>
-No. [[Mole]]s = 2 Mole
+Therefore 40 [[mole]]s of H<sub>2</sub>O are produced.
-Therefore 4 [[mole]]s of O<sub>2</sub> are needed.
+[[mole]]s of CO<sub>2</sub> = 18x40
-[[mole]]s of O<sub>2</sub> = 128g
+'''Yield''' = 720g
 | style="height:20px; width:200px; text-align:left;" |
@@ Line 100: / Line 104: @@
 No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
-No. [[Mole]]s = <math>\frac{20}{40}</math>
+No. [[Mole]]s = <math>\frac{7.3}{36.5}</math>
-No. [[Mole]]s = 0.5 Mole
+No. [[Mole]]s = 0.2 mol
-Therefore 0.5 [[mole]] of HCl is needed.
+Therefore 0.2 [[mole]] of [[Sodium Chloride]] is produced.
-.5 [[mole]] of HCl = 18.25g
+.2 [[mole]] of NaCl = 11.7g
 |}