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10 bytes removed, 12:16, 29 July 2019
Calculating Atomic Number
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>3.82\times10^{7}\times231\times\1times1.67\times10^{-27} = z\times1.60\times10^{-19}</math>
<math>1.4736414\times10^{-17} = z\times1.60\times10^{-19}</math>
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>4.35\times10^{7} = \frac{z\times1.60\times10^{-19}}{(z+30)\times\1times1.67\times10^{-27}}</math>
<math>4.35\times10^{7}\times(z+30)\times\1times1.67\times10^{-27} = z\times1.60\times10^{-19}</math>
<math>(z+30)\times\7times7.2645\times10^{-20} = z\times1.60\times10^{-19}</math>
<math>z\times\7times7.2645\times10^{-20} + 30\times\7times7.2645\times10^{-20}= z\times1.60\times10^{-19}</math>
<math>z\times1.60\times10^{-19} - z\times\7times7.2645\times10^{-20} = 30\times\7times7.2645\times10^{-20}</math>
<math>z(1.60\times10^{-19} - 7.2645\times10^{-20}) = 30\times\7times7.2645\times10^{-20}</math>
<math>z = \frac{30\times\7times7.2645\times10^{-20}}{1.60\times10^{-19} - 7.2645\times10^{-20}}</math>
<math>z = 24.9</math>