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→Calculating Atomic Number
====Calculating Atomic Number====
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| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[proton]]s in a [[Atomic Nucleus|atomic nucleus]] of an [[isotope]] with a an [[Relative Atomic Mass|atomic mass]] of ..... 231[[Unified Atomic Mass Units|u]] and a [[Specific Charge|specific charge]] of 3......82x10<sup>7</sup>Ckg<sup>-1</sup>.| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[proton]]s in a [[Atomic Nucleus|atomic nucleus]] of an [[isotope]] with a 30 [[massneutron]] of ..... s and the a [[Specific Charge|specific charge]] of 4....... for its 5+ [[ion]]35x10<sup>7</sup>Ckg<sup>-1</sup>.
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| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>S.C. = 3.82\times10^{7}</math>Ckg<sup>-1</sup>
<math>Q = z\times1.60\times10^{-19}</math>C
<math>m = 231\times\1.67\times10^{-27}</math>kg
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>S.C. = 4.35\times10^{7}</math>Ckg<sup>-1</sup>
<math>Q = z\times1.60\times10^{-19}</math>C
The [[Relative Atomic Mass|atomic mass]] can be approximated as the number of [[nucleon]]s multiplied by the [[Unified Atomic Mass Units|unified atomic mass unit]].
<math>m = (z+30)\times\1.67\times10^{-27}</math>kg
|-
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
<math>S.C. = \frac{Q}{m}</math>
<math>3.82\times10^{7} = \frac{z\times1.60\times10^{-19}}{231\times\1.67\times10^{-27}}</math>
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
<math>S.C. = \frac{Q}{m}</math>
<math>4.35\times10^{7} = \frac{z\times1.60\times10^{-19}}{(z+30)\times\1.67\times10^{-27}}</math>
|-
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>3.82\times10^{7}\times231\times\1.67\times10^{-27} = z\times1.60\times10^{-19}</math>
<math>1.4736414\times10^{-17} = z\times1.60\times10^{-19}</math>
<math>z = \frac{1.4736414\times10^{-17}}{1.60\times10^{-19}}</math>
<math>z = 92.1<\math>
The [[element]] is [[Uranium]].
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>4.35\times10^{7} = \frac{z\times1.60\times10^{-19}}{(z+30)\times\1.67\times10^{-27}}</math>
<math>4.35\times10^{7}\times(z+30)\times\1.67\times10^{-27} = z\times1.60\times10^{-19}</math>
<math>(z+30)\times\7.2645\times10^{-20} = z\times1.60\times10^{-19}</math>
<math>z\times\7.2645\times10^{-20} + 30\times\7.2645\times10^{-20}= z\times1.60\times10^{-19}</math>
<math>z\times1.60\times10^{-19} - z\times\7.2645\times10^{-20} = 30\times\7.2645\times10^{-20}</math>
<math>z(1.60\times10^{-19} - 7.2645\times10^{-20}) = 30\times\7.2645\times10^{-20}</math>
<math>z = \frac{30\times\7.2645\times10^{-20}}{1.60\times10^{-19} - 7.2645\times10^{-20}}</math>
<math>z = 24.9</math>
There are 25 [[proton]]s so the [[element]] is [[Manganese]].
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