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Specific Charge

974 bytes added, 19:36, 28 July 2019
Calculating the number of Neutrons
====Calculating the number of Neutrons====
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| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[neutron]]s in an [[isotope]] of [[Titanium]] with a [[Atomic Nucleus|nucleus]] of '''specific charge''' of ......4.58x10<sup>7</sup>Ckg<sup>-1</sup>.
| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[neutron]]s in an [[isotope]] of [[Neon]] with the '''specific charge''' of ....... for a [[Neon|Neon 2-]] [[ion]].
|-
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
 
<math>S.C. = 4.58\times10^{7}</math>Ckg<sup>-1</sup>
 
There are 22 [[proton]]s in the [[Atomic Nucleus|nucleus]] of [[Titanium]].
 
<math>Q = 22\times\1.60\times10^{-19}</math>C
 
<math>m = (z + n)\times1.67\times10^{-27}</math>kg
 
Where z is the number of [[proton]]s and n is the number of [[neutron]]s and (z+n) is the [[Relative Atomic Mass|relative atomic mass]].
 
Therefore
 
<math>m = (22 + n)\times1.67\times10^{-27}</math>kg
 
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
|-
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
 
<math>S.C. = \frac{Q}{m}</math>
 
<math>4.58\times10^{7} = \frac{22\times\1.60\times10^{-19}}{(22 + n)\times1.67\times10^{-27}}</math>
 
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
|-
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] and [[Evaluate (Maths)|evaluate]] the equation and , then [[Solve (Maths)|solve]].''' <math>(22 + n) = \frac{22\times\1.60\times10^{-19}}{1.67\times10^{-27}\times4.58\times10^{7}}</math> <math>n = \frac{22\times\1.60\times10^{-19}}{1.67\times10^{-27}\times4.58\times10^{7}} - 22</math> <math>n = 46.0 - 22</math> <math>n = 24.0</math> There are 24 [[neutron]]s in this isotope of [[Titanium]].
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
|}
 
====Calculating Atomic Number====
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